# Line slope calculator 6x+2y=38

**Straight line given by points A[3; 10] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = -3x+19

**Canonical form of the line equation:**6x+2y-38 = 0

**Parametric form of the line equation:**

x = 2t+3

y = -6t+10 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 6.3333

**Y intercept:**y

_{0}= q = 19

**Distance line from the origin:**d

_{0}= 6.0083

**The length of the segment AB: |AB| =**6.3246

**Vector: AB =**(2; -6)

**Normal vector: n =**(6; 2)

**Midpoint of the segment AB: M =**[4; 7]

**Perpendicular Bisector equation:**2x-6y+34 = 0

**Vector OA = (3; 10) ; |OA| = 10.4403**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 55**

**Angle ∠ AOB = 34°38'27″ = 0.6046 rad**